URL Scheme to Return to Safari

[calebaharrison208]

Hi: I've got an action extension through the Workflow App that calls and runs the following URL-shortening (via Bitly) Pythonista script:

import requests
import json
import clipboard
import webbrowser
import console

LongURL = str(clipboard.get())

query_params = {'access_token' : 'MYTOKEN',
                'longUrl' : str(clipboard.get())}
                
endpoint = 'https://api-ssl.bitly.com/v3/shorten'
response = requests.get(endpoint, params= query_params)

data = json.loads(response.content)

if data['status_code'] != 500:
	clipboard.set(data['data']['url'])
	webbrowser.open('safari-'+LongURL)

if data['status_code'] == 500:
	alert = console.alert('URL already shortened!', 'Return to Safari?', 'Safari', hide_cancel_button=True)
	if alert == 0:
		webbrowser.open('safari-'+LongURL)

Is there a URL scheme that will just open Safari in iOS to the last opened tab/page? That is, I currently can't figure out a way to return to Safari after running the Pythonista action without telling Safari to open either a blank page or a specific page (in this case, the initial URL that I shortened, to prevent my returning to Safari from counting as a link view).

I've tried safari-http://a to see if that would work, to no avail. Any help is appreciated!