Help with script

[Jozh]

Is this the best way to say output a list of say the 10 closest birthday? I think not. Thank

import contacts
from datetime import datetime
import operator
import workflow
import dialogs

days_list = []
people = contacts.get_all_people()
now = datetime.now()
for p in people:
  b = p.birthday
  if b:
    next_birthday = datetime(now.year, b.month, b.day)
    if next_birthday < now:
      next_birthday = datetime(now.year + 1, b.month, b.day)
    days = (next_birthday - now).days
    days_list.append({'name': p.full_name, 'days': days})

if not days_list:
  print 'You don\'t have any birthdays in your address book.'
else:
  days_list.sort(key=operator.itemgetter('days'))
  for item in days_list[:1]:
    text = '* %s in %i days' % (item['name'], item['days'])
  for item in days_list[:2]:
    text2 = '* %s in %i days' % (item['name'], item['days'])
  for item in days_list[:3]:
    text3 = '* %s in %i days' % (item['name'], item['days'])
  for item in days_list[:4]:
    text4 = '* %s in %i days' % (item['name'], item['days'])
  for item in days_list[:5]:
    text5 = '* %s in %i days' % (item['name'], item['days'])  
birthday_list = '\n'.join([text, text2, text3,text4,text5]) 
workflow.set_output(birthday_list)```

[ccc]

It looks good to me. The following could save you 9 lines of code:

  fmt = '* {name} in {days} days'
  birthday_list = '\n'.join(fmt.format(**item) for item in days_list[:5])