Find consecutive elements in a list
craigmrock last edited by
Trying to return True if there are duplicate items in a list.
Not working with numbers, and want to allow the user to make a list as long as they want...suggestions?
user = input("What's on your list??: ") def has_consecutive(): items = user.split() #trying to split list into items to compare if (items == items[+1]): #trying to compare one item to the next to find duplicates return True #return true if duplicates are found else: return False #return False if no duplicates are found has_consecutive()```
cvp last edited by cvp
@craigmrock try this
def has_duplicate(): user = '1 2 3 4 2' items = user.split() for i in range(0,len(items)-1): # loop on items except last one if items[i] in items[i+1:]: # check of i-th item exists in next ones return True return False print(has_duplicate())
Checks if duplicates exist but not only consecutive...
if items[i] == items[i+1]: # check if i-th item is equal to next one
Will check consecutive duplicates
enceladus last edited by enceladus
def hasdupelems(l): return len(l) != len(set(l)) print(hasdupelems(['ab', 'cd', 'ab', 'ef'])) print(hasdupelems(['ab', 'cd', 'ef']))