Find consecutive elements in a list

[craigmrock]

Trying to return True if there are duplicate items in a list.
Not working with numbers, and want to allow the user to make a list as long as they want...suggestions?

user = input("What's on your list??: ")
def has_consecutive():
	items = user.split() #trying to split list into items to compare
	if (items[0] == items[+1]): #trying to compare one item to the next to find duplicates
		return True #return true if duplicates are found

	else:
		return False #return False if no duplicates are found 
	
	
has_consecutive()```

[cvp]

@craigmrock try this

def has_duplicate():
	user = '1 2 3 4 2'
	items = user.split()
	for i in range(0,len(items)-1): # loop on items except last one
		if items[i] in items[i+1:]:		# check of i-th item exists in next ones
			return True
	return False
print(has_duplicate())

Checks if duplicates exist but not only consecutive...

		if items[i] == items[i+1]:		# check if i-th item is equal to next one

Will check consecutive duplicates

[enceladus]

def hasdupelems(l):
    return len(l) != len(set(l))
    
print(hasdupelems(['ab', 'cd', 'ab', 'ef']))
print(hasdupelems(['ab', 'cd',  'ef']))