How to reference a switch made with ui Editor?

[Frankson909]

Im playing around with the ui editor. So I made a script and I want to give a switch, which I placed with the editor, a function when the switch is flicked (true/false). If I'm using the action field in the editor, the function is called every time, doesn't matter if I switched on or of. Somehow I cannot figure out how to reference exactly this switch im there where more than on. Can somebody explain it in a easy way?

def switched(sender):
if sender.value == True:
iota_ticker(sw)

#ui.load_view('tickerV2').present('sheet') < I would like to use this view with a switch

sw = ui.Switch(action = switched)
sw.present('sheet')

[cvp]

@Frankson909 Did you define the switch and its action in the UI Editor?
Like this

[Frankson909]

yes I did. But can you give me a line of code to your example? Somehow I could not figure out to reference to my switch. I tried everything. And: if i put my function to the actions field, the function is fired every switch event but I just want thet if true. So I left the action field in the editor empty and put the action to my code.

[Frankson909]

import ui

v = ui.load_view()
v.present('sheet')

def switched_func(sw):
if ui.Switch('switched').value == True:
print('switch is switched')
else:
print('no')

This is not working. Why?

Warning: Could not bind action: name 'switched_func' is not defined

[cvp]

@Frankson909 because your def switched is after the v.present

[cvp]

@Frankson909 with pyui of my picture

import ui

def switched(sender):
	sender.superview.name = str(sender.value)

v = ui.load_view('tickerV2')
v.present('sheet')

# to access attributes of switch in view
v['switch1'].background_color = 'red'
v['switch1'].corner_radius = v['switch1'].height/2

[Frankson909]

Thank u so much!!! I was going crazy already...