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Equally spaced circle in UI

@AZOM, sounds like a school exercise. Wouldn’t it be more useful for your friend to spend the time on cracking it?

No, we are in high school, and this is not a homework or something like that, he just like maths and wants help to “verify” his answer to a question he gets somewhere on the web.

The only thing I am doing wrong is with rounding up numbers (I think it is my only problem) beau a se if 2 values that I compare are like at 0,000001 appart, they are not equal. Also, I am using cos and sin to try to find the three points. And my friend doesn’t program btw.

@AZOM, try
0.1 + 0.2 == 0.3
If you are not satisfied with the result, you might try to use the Decimal class, where you can also
getcontext().prec == 6

@AZOM, meanwhile, for your problem, I would use
ui.Path
with the three points, thenhit_test
with the given point. I do not know whether this would be any more accurate than the method you are using, though. 
Right, now, I don’t have my program, but I’m going to send it at ~5h pm.

@AZOM, going to get my beauty sleep now, but here’s what I meant by the hit test:
import random import ui import vector random_angle = lambda: random.random() * 360 p = ui.Path() point = vector.Vector(0, 1) point.degrees = random_angle() p.move_to(*point) print(point) for _ in range(2): point.degrees = random_angle() p.line_to(*point) print(point) p.close() print('IN' if p.hit_test(0.5,0) else 'OUT')

So, are you trying to input 3 points (not all colinear) and find the circle (radius and x,y). Then want to determine if a fourth point is on the edge of the circle?
A simple method is to just subtract the center, then compute the length, then compare to the circle radius. But, as you found, you want to use abs(point_to_center_distcircle_radius)< threshold, where you'll have to decide what is an acceptable threshold.