Pythonista Upload Photos from Library

DavinE

Hey Guys,

i Have a new idea and a new Question xD

is it Possible to select multiple Photos from my complete Photo-Library and upload it to my server via ftps ?

i found this on the documentation:

import photos
assets = photos.pick_asset(title='Pick some assets', multi=True)
print(assets)

here i can select some vids and pics.
but how i get the path of the files to use it in ftp ?
and nice to have were to rename each file

is this possible ?

cvp

@DavinE use, for each asset, something like

			filename = str(ObjCInstance(asset).valueForKey_('filename'))
			pil = asset.get_image()
			pil.save(filename, quality=95)

Then you can send your local file and remove it after.

DavinE

This post is deleted!

DavinE

@cvp,

this is my code:

import os, sys
import photos

assets = photos.pick_asset(title='Pick some assets', multi=True)
print(f'assets: {assets}')
for asset in assets:
    pil = asset.get_image(original=False)
    pil.show()
    #print(filename)
    filename = 'test.PNG'
    pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)

this works good but is it possible to change the filename like this:

    pil = asset.get_image(original=False)
    console.quicklook(pil)
    #print(filename)
    filename = '%s%s' % (console.input_alert('Rename File', 'Message: rename File', hide_cancel_button=False), '.PNG')
    pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)

or better show the image in console.input_alert thus you know what you are renaming ?

cvp

@DavinE for the file name, testing your code would be the best answer 🙄

cvp

@DavinE console.quicklook needs a path, not a pil

    filename = 'test.PNG'
    console.quicklook(filename)

cvp

@DavinE this works

    pil = asset.get_image(original=False)
    #pil.show()
    #print(filename)
    filename = 'test.PNG'
    console.quicklook(filename)
    filename = '%s%s' % (console.input_alert('Rename File', 'Message: rename File', hide_cancel_button=False), '.PNG')
    pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)

DavinE

@cvp said:

@DavinE this works

    pil = asset.get_image(original=False)
    #pil.show()
    #print(filename)
    filename = 'test.PNG'
    console.quicklook(filename)
    filename = '%s%s' % (console.input_alert('Rename File', 'Message: rename File', hide_cancel_button=False), '.PNG')
    pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)

No this works not because console.quicklook(filename) did not exists pil.save is called later...
i think what i want to do this don't works..

DavinE

@cvp said:

@DavinE console.quicklook needs a path, not a pil
    filename = 'test.PNG'
    console.quicklook(filename)

i Know i get an error xD

DavinE

@cvp said:

@DavinE for the file name, testing your code would be the best answer 🙄

i removed the Question ^^ i'm too fast

cvp

@DavinE thus, all is ok?

cvp

@DavinE said:

No this works not because console.quicklook(filename) did not exists pil.save is called later...
i think what i want to do this don't works..

You are right, sorry. But you can always rename your file after saving it as local.
If you only need to upload the file and to not keep a local copy, usealways the same temp name for local save, thus the quicklook will work.

get asset
pil.save as local tempname
quicklook tempname
ask name
Upload to name
remove tempname local

DavinE

@cvp said:

@DavinE said:

No this works not because console.quicklook(filename) did not exists pil.save is called later...
i think what i want to do this don't works..

You are right, sorry. But you can always rename your file after saving it as local.
If you only need to upload the file and to not keep a local copy, usealways the same temp name for local save, thus the quicklook will work.

yes, i got the same idea ;)

here's the code:

assets = photos.pick_asset(title='Pick some assets', multi=True)
print(f'assets: {assets}')
for asset in assets:
    pil = asset.get_image(original=False)
    pil.save(os.path.join(os.path.dirname(sys.argv[0]), 'Images', filename), quality=95)

    for image in os.listdir(os.path.join(os.path.dirname(sys.argv[0]), 'Images')):
        console.quicklook((os.path.join(os.path.dirname(sys.argv[0]), 'Images', image)))
        filename = '%s%s' % (console.input_alert('Rename File', 'Message: rename File', hide_cancel_button=False), '.PNG')
        # Upload......

Thanks for your help @cvp

cvp

@DavinE I have edited my post just before reading your last one

DavinE

@cvp the post above yours or which one ?

cvp

If you want to ftp upload the picked photos, I think you get the asset a binary data and to upload it without passing via a local copy.
Of course, if you want to show the photo without a local file, you can't use quicklook but an ImageView could be sufficient to show the image....

cvp

@DavinE said:

the post above yours or which one ?

Forget it because you found a solution

cvp

I don't have any FTP server accessible just now, but you can test this

#pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)
temp = io.BytesIO()
pil.save(temp, format='JPEG', quality=95)
temp.seek(0)
#session.storbinary('STOR xxxxx.jpg' , temp)

The pil.save needs a format because, without file name, file type would be unknown

cvp

Please, if you try this one, please let me know if it is ok

import console
import os, sys
import photos
import io
import ui

assets = photos.pick_asset(title='Pick some assets', multi=True)
for asset in assets:
    pil = asset.get_image(original=False)
    iv = ui.ImageView()
    iv.image = asset.get_ui_image()
    iv.present('fullscreen')
    #pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)
    temp = io.BytesIO()
    pil.save(temp, format='JPEG', quality=95)
    temp.seek(0)
    filename = '%s%s' % (console.input_alert('Rename File', 'Message: rename File', hide_cancel_button=False), '.PNG')
    #session.storbinary('STOR '+filename , temp)

DavinE

@cvp said:

Please, if you try this one, please let me know if it is ok

import console
import os, sys
import photos
import io
import ui

assets = photos.pick_asset(title='Pick some assets', multi=True)
for asset in assets:
    pil = asset.get_image(original=False)
    iv = ui.ImageView()
    iv.image = asset.get_ui_image()
    iv.present('fullscreen')
    #pil.save(os.path.join(os.path.dirname(sys.argv[0]), filename), quality=95)
    temp = io.BytesIO()
    pil.save(temp, format='JPEG', quality=95)
    temp.seek(0)
    filename = '%s%s' % (console.input_alert('Rename File', 'Message: rename File', hide_cancel_button=False), '.PNG')
    #session.storbinary('STOR '+filename , temp)

this looks nice.
i try it.